Japanese Lesson 2
Lesson Table

CW: Whole-class work
SW: Seatwork

  
Time Description of Activity Description of Content
00:01  Pre-Lesson Activity  
00:15 CW: Sharing Homework
(6 min 45 sec)

Solve inequalities. (Teacher assign six students to write the solutions on the board)

(1) 6x-4<4x+10 (2) 2x-67x+4 (3) 1.2x-4.2>0.4x+0.6
6x-4x<+10+4 2x-7x4+6 (1.2x-4.2>0.4x+0.6)x10
2x<14 -5x10 12x-4x>6+42
8x>48
x<7  x2
    x>6
   
(4) 3(x+4) > 5x+2 (5) 4(x-2)5(2x-3) (6) 1.8x+2>0.5x+0.7
3x+12 > 5x+2 4x-810x-15 18x+20>5x+7
3x-5x>2-12 4x-10x-15+8 18x-5x>7-20
* -2x < -10 -6x-7 13x>-13
x x>-1
x<5    

*(Corrected)
In the above solution,
-2x < -10 should be
-2x > -10
07:00 CW: Setting Up Tasks/Situations

(3 min 24 sec)

 (Teacher states lesson goal) “Today will be the final part of word problems.”
08:51 (Chalkboard)
You would like to buy 10 cakes all together for less than $21 in which one cake is $2.30 each and the other cake is $2.00 each. If you want to buy as many $2.30 cakes as possible, what is the maximum number that you can buy?
10:24 "Think about what you need to do to find out how many you can buy and find the answer."
10:34 SW: Working on Tasks/Situations
(5 min 24 sec)		  
15:58 CW: Sharing Tasks/Situations
(9 min 24 sec)
Thinking method 1
$2.30 cake         x 3 .....x 8 x 9 x 10
  6.90   20.70 $23.00
$2.00 cake x 7   x 1  
  14.00
20.90		   2.00
22.70		  
   
<Thinking method 2>
You want to buy ten $2.30 cakes which would cost $23

You are short $2.00
You want to substitute some with $2.00 cakes to make up the shortage. How many do you have to substitute?
If you buy seven $2.00 cakes, you save $2.10, which would take care of the shortage of money
Which means you buy three $2.30 cakes

   
<Thinking method 3>
Make the number of $2.30 cakes x.
Then the number of $2.00 cakes becomes 10-x.		  
$2.30 $2.00
x 10-x
230x+200 (10-x)2100
 25:34 CW: Working On Tasks/Situations
 (9 min 4 sec)		 (The teacher passes out worksheets.)
"We are going to try and do [the problem] using an inequality equation."
Buy x amount of $2.30 cake

[Equation]
230x+200(10-x)2100
230x+2000-200x2100
230x-200x2100-2000
30x100
x(3.3….)
Answer: You can buy up to three of $2.30 cakes.

(Chalkboard: Setting up an inequality equation facilitates finding the answer.)
34:39 CW: Setting Up Tasks/Situations
(1 min 5 sec)		 "There are two problems on the right side. Try to set up an inequality equation by your self in the same way and try to solve the problem."
(Worksheet)
You would like to buy 15 pears and persimmons and a basket all together and for less than $10 in which one pear costs 70 cents each, one persimmon costs 50 cents each, and a basket costs 80 cents. You want to buy more pears than persimmons. Up to how many pears can you buy?
35:44 SW: Working On Tasks/Situations Individually
(11 min 29 sec)		  
47:15 CW: Sharing Tasks/Situations
(2 min 33 sec)
[Student 1]      
  $1.20 apples        70 cent tangerines        Total
Amount x 20-x 20
Sum 120x 70(20-x) 2000
120x+70(20-x) 2000
120x+1400-70x2000
120x-70x2000-1400
50x600

x12
Answer: 12 apples		      
   
[Student 2]        
  70 cent pears       50 cent persimmons       Basket        
Total        
Amount x 15-x 15  
Sum 70x 50(15-x) 80 1000
70x+50(15-x)+801000
70x+750-50x+801000
70x-50x1000-750-80
20x170


Answer: 8 pears		        
49:48 CW: Teacher Talk/Demonstration
(39 sec)		 (Teacher states lesson summary) “When you work out problems instead of counting things one by one and finding the number, it’s usually easier if you set up an inequality and find the answer.”
50:27
~51:38		  Post-Lesson Activity (The teacher passes out worksheets for the next lesson.)
 
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